-1.5x^2+24=0

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Solution for -1.5x^2+24=0 equation: 



-1.5x^2+24=0

a = -1.5; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-1.5)·24
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-1.5}=\frac{-12}{-3}
=+4
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-1.5}=\frac{12}{-3}
=-4
$

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